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HTML5+JavaScript实现消消乐游戏
点击两个相邻的方块来交换它们位置。
如果交换后形成三个或更多相同图案的方块连成一线，这些方块会被消除。
消除后，上方的方块会下落填补空缺，顶部会生成新的方块。
每消除一个方块得10分。例如，如果一次消除了4个方块，玩家将得到40分。
运行效果如下图：
源码如下：
<!DOCTYPE html>
<html lang="zh-CN">
<head><meta charset="UTF-8"><meta name="viewport" content="width=device-width, initial-scale=1.0"><title>基础消消乐游戏 - Emoji版</title><style>body {display: flex;flex-direction: column;justify-content: center;align-items: center;height: 100vh;margin: 0;background-color: #f0f0f0;font-family: Arial, sans-serif;}#gameContainer {display: flex;flex-direction: column;align-items: center;}canvas {border: 2px solid #000;margin-bottom: 10px;}#scoreDisplay {font-size: 24px;margin-bottom: 10px;}</style>
</head>
<body><div id="gameContainer"><div id="scoreDisplay">分数: 0</div><canvas id="gameCanvas" width="400" height="400"></canvas></div><script>const canvas = document.getElementById('gameCanvas');const ctx = canvas.getContext('2d');const scoreDisplay = document.getElementById('scoreDisplay');const GRID_SIZE = 8;const CELL_SIZE = canvas.width / GRID_SIZE;const EMOJIS = ['☮', '⚜', '♾ ', '☯', '⚛', '✳'];let grid = [];let selectedCell = null;let score = 0;function initGrid() {for (let i = 0; i < GRID_SIZE; i++) {grid[i] = [];for (let j = 0; j < GRID_SIZE; j++) {grid[i][j] = EMOJIS[Math.floor(Math.random() * EMOJIS.length)];}}}function drawGrid() {ctx.clearRect(0, 0, canvas.width, canvas.height);ctx.font = `${CELL_SIZE * 0.8}px Arial`;ctx.textAlign = 'center';ctx.textBaseline = 'middle';for (let i = 0; i < GRID_SIZE; i++) {for (let j = 0; j < GRID_SIZE; j++) {ctx.fillText(grid[i][j], i * CELL_SIZE + CELL_SIZE / 2, j * CELL_SIZE + CELL_SIZE / 2);}}if (selectedCell) {ctx.strokeStyle = 'black';ctx.lineWidth = 2;ctx.strokeRect(selectedCell.x * CELL_SIZE, selectedCell.y * CELL_SIZE, CELL_SIZE, CELL_SIZE);}}function checkMatches() {let matched = [];// 检查水平匹配for (let j = 0; j < GRID_SIZE; j++) {let streak = 1;for (let i = 1; i < GRID_SIZE; i++) {if (grid[i][j] === grid[i-1][j]) {streak++;} else {if (streak >= 3) {for (let k = i - streak; k < i; k++) {matched.push({x: k, y: j});}}streak = 1;}}if (streak >= 3) {for (let k = GRID_SIZE - streak; k < GRID_SIZE; k++) {matched.push({x: k, y: j});}}}// 检查垂直匹配for (let i = 0; i < GRID_SIZE; i++) {let streak = 1;for (let j = 1; j < GRID_SIZE; j++) {if (grid[i][j] === grid[i][j-1]) {streak++;} else {if (streak >= 3) {for (let k = j - streak; k < j; k++) {matched.push({x: i, y: k});}}streak = 1;}}if (streak >= 3) {for (let k = GRID_SIZE - streak; k < GRID_SIZE; k++) {matched.push({x: i, y: k});}}}return matched;}function removeMatches(matches) {matches.forEach(cell => {grid[cell.x][cell.y] = null;});//updateScore(matches.length);}function updateScore(matchCount) {score += matchCount * 10;scoreDisplay.textContent = `分数: ${score}`;}function fillBlanks() {for (let i = 0; i < GRID_SIZE; i++) {let blanks = 0;for (let j = GRID_SIZE - 1; j >= 0; j--) {if (!grid[i][j]) {blanks++;} else if (blanks > 0) {grid[i][j + blanks] = grid[i][j];grid[i][j] = null;}}for (let j = 0; j < blanks; j++) {grid[i][j] = EMOJIS[Math.floor(Math.random() * EMOJIS.length)];}}}function swapCells(cell1, cell2) {const temp = grid[cell1.x][cell1.y];grid[cell1.x][cell1.y] = grid[cell2.x][cell2.y];grid[cell2.x][cell2.y] = temp;}canvas.addEventListener('click', (event) => {const rect = canvas.getBoundingClientRect();const x = Math.floor((event.clientX - rect.left) / CELL_SIZE);const y = Math.floor((event.clientY - rect.top) / CELL_SIZE);if (selectedCell) {if ((Math.abs(selectedCell.x - x) === 1 && selectedCell.y === y) ||(Math.abs(selectedCell.y - y) === 1 && selectedCell.x === x)) {swapCells(selectedCell, {x, y});let matches = checkMatches();if (matches.length === 0) {swapCells(selectedCell, {x, y});} else {let totalMatches = 0;while (matches.length > 0) {totalMatches += matches.length;removeMatches(matches);fillBlanks();matches = checkMatches();}updateScore(totalMatches); // 在所有匹配处理完后更新分数}}selectedCell = null;} else {selectedCell = {x, y};}drawGrid();});function gameLoop() {drawGrid();requestAnimationFrame(gameLoop);}initGrid();gameLoop();</script>
</body>
</html>