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提示#xff1a;没有基础请先看看基础部分的讲解#xff0c;否则看不懂
1#xff0c;编写函数#xff0c;实现判断是否无位置参数#xff0c;如无参数#xff0c;提示错误
代码#xff1a;
#bash/bin
function a() {b$# #判断传入的参数个数
# echo $b…题目
提示没有基础请先看看基础部分的讲解否则看不懂
1编写函数实现判断是否无位置参数如无参数提示错误
代码
#bash/bin
function a() {b$# #判断传入的参数个数
# echo $bif [ $b -eq 0 ] # 看参数个数是不是等于0 thenecho noelseecho yesfi
}
a1当不传入参数时结果为
no2当传入参数时结果为
yes2编写函数实现两个数字做为参数返回最大值
代码
function a() { # 定义函数num1$1 # 获取第一个参数
# echo num1:$num1num2$2
# echo num2:$num2if [ $num1 -gt $num2 ] # 2个参数进行比较thenecho $num1 # 返回第一个参数elseecho $num2 # 返回得第二个参数fi
}
c$(a 200 300) # 传入2个参数并且将返回值赋值给c
echo the $c is more big运行输出结果
[rootlocalhost ~]# bash functiontest.sh
the num1:200
num2:300
300 is more big3编写函数实现两个整数位参数计算加减乘除
代码
a(){one$1two$2echo $one $two expr $one $twoecho $one - $two expr $one - $twoecho $one * $two expr $one \* $twoecho $one / $two expr $one / $twoprintf $one / $two expr $one / $two\n}
a 2 3运行结果
[rootlocalhost ~]# bash functiontest.sh
2 3 5
2 - 3 -1
2 * 3 6
2 / 3 0
2 / 3 04、将/etc/shadow文件的每一行作为元数赋值给数组
代码
function a(){awc -l /etc/shadow | cut -d -f1 # 将目标文件进行剪切提取需要的数据这里代表数据个数
for i in seq $a
dobexpr $i - 1 # 数组下标arr[$b]awk NR$i{print} /etc/shadow # 将对应的哪一行数据放入到数组
done
}
a
echo ${arr[0]} # 打印数组的第一个元素
echo ${arr[1]} #第二个
echo ${arr[2]}
echo ${arr[3]}以上的结果显示为: 结果的验证可以用cat 命令对目标文件进行对比
[rootlocalhost ~]# bash functiontest.sh
root:$6$SqQF33Q5poRxzqNJ$mAZ7EJuymCGVS6HxSAinq4danhF48kUbkyg/Kck3VJ8mIO5tDJlrsbQ04.aXbUb63rif82rIR/Xuatvcdj6Bp1::0:99999:7:::
bin:*:19121:0:99999:7:::
daemon:*:19121:0:99999:7:::
adm:*:19121:0:99999:7:::5使用关联数组统计文件/etc/passwd中各个用户的shell类型
代码
function a(){read -p which users shell type that you want find?: shell_type # 提示加读取输入的变量declare -A arry # 必须声明关联数组lwc -l /etc/passwd | cut -d -f1 # 计算数据的条数for i in seq $ldo
# ass-arry[expr $i - 0] indexcat /etc/passwd | awk BEGIN{FS:}{print $1} | awk NR$i{print} # 关联数组的下标# echo index $indexdeclare -A arryarry[$index]cat /etc/passwd | awk BEGIN{FS:}{print $7} | awk NR$i{print} # 关联数组的值doneecho the user $shell_types shell type is ${arry[$shell_type]} # 格式化输出
}
a
运行的结果
[rootlocalhost ~]# bash functiontest.sh
which users shell type that you want find?:fu
the user fus shell type is /bin/bash[rootlocalhost ~]# bash functiontest.sh
which users shell type that you want find?:root
the user roots shell type is /bin/bash[rootlocalhost ~]# bash functiontest.sh
which users shell type that you want find?:bin
the user bins shell type is /sbin/nologin6使用关联数组按扩展名统计指定目录中文件的数量
代码
function a() {read -p input a file path (absolute):(such as input /etc/) path # 输入路径read -p which type of file are you count ?:(such as input txt or sh ...) type1 # 输入文件类型als -l $path | awk {print $9} | grep ^[^$] | awk BEGIN{FS.}{print $2} # 看有几个文件有后缀名declare -A arrfor i in $ado# echo file type: $iarr[$i]expr ${arr[$i]} 1 # 对文件类型计数表示该类型文件个数doneecho the file of type $type1 have ${arr[$type1]}
}
a运行结果如下结果的验证可以用自己数
[rootlocalhost ~]# bash functiontest.sh
input a file path (absolute):(such as input /etc/)/etc/
which type of file are you count ?:(such as input txt or sh ...)conf
the file of type conf have 36[rootlocalhost ~]# bash functiontest.sh
input a file path (absolute):(such as input /etc/)/etc/
which type of file are you count ?:(such as input txt or sh ...)d
the file of type d have 247编写函数 判断是否有参数存在为Ok不存在为FAILED要求绿色OK和红色FAILED
代码
function a() {b$#
## echo $bif [ $b -eq 0 ]thenecho -e \e[31m failde \e[0m;elseecho -e \e[32m ok \e[0m;fi
}
a 1
