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2023每日刷题（六）

Leetcode—34.在排序数组中查找元素的第一个和最后一个位置

实现代码

/*** Note: The returned array must be malloced, assume caller calls free().*/
int lower_bound(int *arr, int numsSize, int target) {// 左闭右开区间[left, target)int left = 0, right = numsSize;int mid;while(left < right) {mid = left + (right - left) / 2;if(arr[mid] < target) {left = mid + 1;} else {right = mid;}}return left;
}int* searchRange(int* nums, int numsSize, int target, int* returnSize){int *ans = (int *)malloc(sizeof(int) * 2);*returnSize = 2;ans[0] = -1;ans[1] = -1;int left = lower_bound(nums, numsSize, target);int right = lower_bound(nums, numsSize, target + 1) - 1;if(numsSize != 0 && left != numsSize && nums[left] == target) {ans[0] = left;ans[1] = right;} return ans;
}

运行结果

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